Programming in JAVA

Norm of a Number in Java Question :   Write a program to calculate Norm of a Number. Norm of a number is square root of sum of squares of all digits of the number. Example :- Input : 68             6 X 6 + 8 X 8 = 100 ;  Square root of 100 = 10 Output : Norm of 68 is 10. Logic  :- First input number. Copy the input number in another variable extract each digit of the number Store the sum of squares of the digit of the number in a variable say 's' Print the square root of the result. (i.e. square root of 's' ) Compile and run the program Note  : To understand the program clearly watch this video :  https://youtu.be/tXDl56akraE

Factorial Series in Java Question :   Write a program to print the following series. S = 2! + (2! + 3!) - (2! + 3! + 5!) + (2! + 3! + 5! + 7!)......... n terms The above series is very easy to solve Logic  :- First input number of terms The nth term will contain 'n' number of terms (ex- if n = 2, then it will contain 2 terms i.e. (2! + 3!)) calculate the nth term by first finding the first 'n' number of prime numbers Now, calculate factorial of each prime number Add the factorials of all the prime numbers Now if the nth term is odd and not the first then it will be a negative term else it will be a positive term Store the result in the variable accordingly Print the result Note : To understand the program clearly watch this video :  https://youtu.be/CRX9zDJYY4U