Norm of a Number in Java
Norm of a Number in Java Question : Write a program to calculate Norm of a Number. Norm of a number is square root of sum of squares of all digits of the number. Example :- Input : 68 6 X 6 + 8 X 8 = 100 ; Square root of 100 = 10 Output : Norm of 68 is 10. Logic :- First input number. Copy the input number in another variable extract each digit of the number Store the sum of squares of the digit of the number in a variable say 's' Print the square root of the result. (i.e. square root of 's' ) Compile and run the program Note : To understand the program clearly watch this video : https://youtu.be/tXDl56akraE