Armstrong Number in JAVA

Armstrong Number

Program to check a number is Armstrong or Not.

A Number is said to be Armstrong Number if it is equal to the sum of cubes of its digits.

Example : 0, 1, 153, 370, 371, 407 etc.

Program below:-

import java.io.*;

import java.util.*;

class Armstrong

{

    public static void main(String args[]) throws IOException

    {

        int n,m,rev,s=0;

        Scanner in= new Scanner(System.in);

        System.out.println("Enter the number");

        n= in.nextInt(); // Enter Number from user

        m=n; // storing entered number in m variable

        while(n>0)

        {

            rev= n%10; // extracting last digit of the number

            s=s+rev*rev*rev; // store cube of the digit

            n=n/10; // extracting quotient of the number

        }

        if(s==m) // checking entered number with cubes of its digits

        {

            System.out.println("It is an armstrong number : "+m);

        }

        else

        {

            System.out.println("It is not an armstrong number : "+m);

        }

    }// end of main method

}// end of class

All the best :)

Watch this Program Video : https://youtu.be/ThIt0vCoQTc