Neon Number in JAVA

Neon Number in JAVA

A Neon Number is a number whose sum of digits of square of the number is equal to the number.

Example : Input number is 9, its square is 9*9 = 81 and sum of the digits of square is 9. i.e. 9 is a neon number

Algorithm and Program below :-

ALGORITHM :-

1. Get the number to check for Neon Number
2. Get the square of the number in another variable
3. Store the sum of digits of square number in a variable
4. Compare the sum of the digits with the number
5. If both are equal print "Neon Number"
6. If not print "Not a Neon Number"

PROGRAM below :-

import java.io.*;

import java.util.*;

class Neon

{

    public static void main(String args[])

    {

        Scanner in= new Scanner(System.in);

        int n,p,rev,s=0;

        System.out.println("Enter Number");

        n= in.nextInt(); // Input number from user

        p=n*n; // storing the square of the number

        while(p>0)

        {

            rev=p%10; // it extract last digit of the number

            s=s+rev; // store the sum of digits of square of original number

            p=p/10; // it extract all digit except the last

        }

        if(n==s) // if number is equal to the sum of its square's digits

        {

            System.out.println("It is Neon Number : "+n);

        }

        else

        {

            System.out.println("It is not Neon Number : "+n);

        }

    } // end of main method

} // end of class